square root of 41
Points: (2, 1) and (14, 6) Distance: 13
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
3.61 units
Point 1 = (x1, y1)Point2 = (x2, y2)d = ((x2 -x1)2 + ( y2 -x2 )2 )0.5
A vertical line in the xy coordinate plane would represent the line of an equation such as x = 1 or x = -4.
The distance formula, d=√(x2−x1)2+(y2−y1)2 d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 , is derived from the Pythagorean theorem and gives us the distance between any two points, (x1,y1) ( x 1 , y 1 ) and (x2,y2) ( x 2 , y 2 ) , in a rectangular coordinate plane.
Compare the distance to a known length. Measure. If you know the coordinates of the two dots in an orthogonal coordinate system, use Pythagoras' theorem to find the distance. Say point 1 has coordinate (Ax,By) and point 2 has coordinate (Cx,Dy) then the distance between 1 and 2 is the square root of ((C-A)2 + (D-B)2))
If you mean (-2, -1) and (5, 3) then it is the square root of 65 which is about 8.062 to three decimal places
If p=(-7) and d=(-1) then the distance from p to d is determined by the distance formula for the one dimensional coordinate line:D=(x2-x1) d=x2, p=x1D=(-1)-(-7) = (-1)+7 = 6The positive number means the direction from p to d is from left to right on the coordinate line.
Using the distance formula from (3, 1) to (7, 1) is 4 units
Points: (2, 1) and (14, 6) Distance: 13
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
If you mean points of: (2, 1) and (14, 6) then the distance is 13
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
3.61 units
If you mean points of (5, 5) and (1, 5) then the distance is 4
3.61 units