Assuming the impact was elastic, Car1 will not be at rest, and Car2 will move at 20m/s at the same direction Car1 was previously moving.
10 m/s
5 m/s *apex:)
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
Might be 20 kg-m/s
10 m/s
10,000
10 m/s
7,500 Kg-m/s
Their speed after the collision would be 5 m/s. This can be calculated using the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision in an isolated system. Since Car 1 was initially at rest (0 m/s) and Car 2 was moving at 10 m/s, their total momentum before the collision would be m * v = 1000 kg * 10 m/s = 10000 kgā m/s. After the collision, this total momentum would be divided between the two cars, resulting in a speed of 5 m/s for the combined system.
10,000 kg-m/s
10,000 kg-m/s
5 m/s *apex:)
10,000 kg-m/s
They move with a speed of 3 ms^-1.
They move with a speed of 3 ms^-1.
5 m/s APPEX ;)
Law of Conservation of Momentum: The total momentum after the collision is equal to the total momentum before the collission.