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Answered 2011-01-24 10:43:29

252/1024 or 0.246.

One method of calculating it is this: The total number of outcomes possible by tossing a coin 10 times is 2 to the 10th, which is 1024. In addition, getting 5 heads in 10 tosses is like arranging 5 identical objects in 10 spaces (the remaining 5 spaces are by default Tails), which can be done in 10C5 ways, which is 252. So the probability of getting 5 heads is 252/1024.

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By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%


The probability of tossing two heads in two coins is 0.25.



No, the possible results of two coin flips are; HH HT TH TT The probability of getting exactly one tail is 1/2 or 50%.


The probability that exactly one will land heads up is 0.15625



The probability of tossing two coins that are different is 1 in 2, or 0.5.The probability of tossing something on the first coin is 1. The probability of not matching that on the second coin is 0.5. Multiply 1 and 0.5 together, and you get 0.5.



Assuming it is a fair coin, the probability is 1/24 = 1/16.




The probability for that is (1/2)4 = 1/16.


Zero. Since coins land on Heads or Tails and not numbers.





The probability of tossing 6 heads in 6 dice is 1 in 26, or 1 in 64, or 0.015625. THe probability of doing that at least once in six trials, then, is 6 in 26, or 6 in 64, or 3 in 32, or 0.09375.


3/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8


When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban


Depends on if you are talking about probability. If so then yes. If not then 100 coins is more than 1 coin.


The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128


If they are fair coins, the probability is 0.25


The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256


Coin tosses are what we call Independent Events, meaning that the results of one toss have no effect on the next toss or any thereafter. Therefore the probability of each toss is 1/2. If, however, you want to know the probability of tossing two coins, and each coin landing heads-up, you simply multiply their probabilities together, resulting in 1/4.


it is 1/3 uhhh be specific because on apex its 3/8



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