The 8085 is an 8-bit microprocessor.
Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
The 8086 is a 16 bit microprocessor because Intel designed it that way. It was considered to be the next logical evolution of the 8085, which is an 8 bit processor.
The number of bits that a processor is called is generally the fundamental accumulator size. In the 8086, AX is 16 bits in size, while in the 8085 A is 8 bits in size.
The 8085 microprocessor is an 8-bit microprocessor.
Yes, the Intel 8085 is an 8 bit microprocessor.
no . 8085 is an 8 bit processor
It is a 16-bit processor .
8085 is a 8 bit microprocessor and so A register which is also known as accumulator is also 8 bit.
8086 is a 16bit processor.
8085 is a microprocessor designed by Intel
+5v supply is alone needed for Intel 8085 Microprocessor
There are 74 instructions in the 8085 microprocessor.
One.
The '8085' in the 8085 microprocessor is the designation given to the microprocessor by Intel. The '5' means it is a single power supply (5 volt) version of the 8080, with enhancements.
+5v necessary for microprocessor 8085.
8085 is a 8 bit microprocessor designed by Intel Co.
The 8085 is an 8 bit microprocessor. It cannot directly handle 32 bit data. That said, it is possible to write a routine that can handle 32 bit data, just 8 bits at a time.
with neat diagram explain the system bus structure of 8085
The 8085 has a 16 bit address bus.