No, that electron configuration does not exist. After the 3p orbital fills with electrons, the next lowest energy orbital is 4s. After 4s contains 2 electrons, then 3d can accept electrons, upto 10. The element with this electron configuration is zinc, one of the transitional metals. Although 3d is full, those electrons can be 'valence' electrons and given to non-metals to form ions, such as Zn+2 or Zn+4. So 3d really acts like a 4th shell orbital and will still be quite reactive even when full.
To see just how reactive these electrons are, look at the YouTube videos embedded in this site: http://www.chemicool.com/elements/zinc.html.
yes, Cu+ has a pseudo-noble-gas electron configuration
it all depends on the electron configuration if it is positive or negative, you have to look at the transition metals and valence electrons and determine the charge and use the formula n-11s^2 2s^2 2p^6 3s^2 3p^6 3d^10
The pseudo noble-gas electron configuration has the outer three orbitals filled, the s, p and d- s2p6d10 (18 electrons total) and so is fairly stable. Elements that attain this electron configuration are at the right side of the transition metals (d-block). Br-, I-, Se2-
The noble gas electron configuration of radon is [Xe]4f145d106s26p6.
Calcium loses two electrons to obtain a noble-gas electron configuration.
Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration. Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration.
no. it doesn't
Silver needs 7 more electrons to reach a "pseudo-noble gas" configuration.
yes, Cu+ has a pseudo-noble-gas electron configuration
The pseudo noble-gas electron configuration has the outer three orbitals filled, the s, p and d- s2p6d10 (18 electrons total) and so is fairly stable. Elements that attain this electron configuration are at the right side of the transition metals (d-block). Br-, I-, Se2-
One
it all depends on the electron configuration if it is positive or negative, you have to look at the transition metals and valence electrons and determine the charge and use the formula n-11s^2 2s^2 2p^6 3s^2 3p^6 3d^10
The pseudo noble-gas electron configuration has the outer three orbitals filled, the s, p and d- s2p6d10 (18 electrons total) and so is fairly stable. Elements that attain this electron configuration are at the right side of the transition metals (d-block). Br-, I-, Se2-
The "Noble gas electron configuration," or the condensed electron configuration, for F is [He] 2s2 3p5.
One electron 'off' to become Ag+ = [Kr] 4d10 5s0
The noble gas electron configuration of radon is [Xe]4f145d106s26p6.
Losing an electron cesium has a noble gas configuration.