To be divisible by 5, the last digit must be 0 or 5.
The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.
No it is not.
They are both divisible by 7, so it would be 4/5.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
No, 549 is not divisible by 5.
1,2,4,7,14,28 28=2 squared times 7
Yes, all numbers that are divisible by 5 are also divisible by 10. This is because 10 is a multiple of 5. When we say that a number is divisible by 5, we mean that it can be evenly divided by 5 with no remainder. When we say that a number is divisible by 10, we mean that it can be evenly
28 is not divisible by 3.
28 is divisible by 1, 2, 4, 7, 14, 28.
28 is divisible by: 1, 2, 4, 7, 14, 28.
28 and its multiples.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
28, 56, 84, and all other multiples of 28 that are factors of other numbers are also divisible by 28.
140 is divisible by these numbers: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140.
evenly divisible 28 times
They are both divisible by 7, so it would be 4/5.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
yes 4x7=28
No.