2H2O ==> 2H2 + O2
Oxidation number of H on the left is 1+ and on the right it is zero. H has been reduced.
Oxidation number of O on the left is 2- and on the right it is zero. O has been oxidized.
YES, this is a redox reaction.
Yes.
Hydrogen is Oxidized:
H2 --> 2H+
Oxygen is Reduced
O2 --> 2O-
There are a number of different ways in which water can be formed, so you would have to be more specific in order to get a meaningful answer to your question.
It can be, depending on the reaction in question.
Water may be a reactant.
2H2O--->2H2 + O2 is a redox reaction because electrons are exchanged during electrolysis.
2Mg + O2------> 2MgO
i can't really read that reaction but! if there is an element by itself in either the reactant or the product side of the reaction QUICKLY think REDOX because the oxidation states for ANY element is 0 by themselves and when they form compounds they either oxidize or reduce to their oxidation state hope i helped
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
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yes
2H2O--->2H2 + O2 is a redox reaction because electrons are exchanged during electrolysis.
combustion
2Mg + O2------> 2MgO
No, there is no change in any oxidation states.
The reaction is 2Mg + O2 ----> 2MgO Mainly it is a Composition reaction (also called as combination or syntesis reaction). But also catogrised in redox reaction & combution reaction.
A chemical change, redox reaction: 2Fe(s) + O2(g) --> 2FeO(s)
decomposition reaction
endothermic
i can't really read that reaction but! if there is an element by itself in either the reactant or the product side of the reaction QUICKLY think REDOX because the oxidation states for ANY element is 0 by themselves and when they form compounds they either oxidize or reduce to their oxidation state hope i helped
The combustion reaction of heptane is:C7H16 + 11 O2 = 7 CO2 + 8 H2O
synthesis reaction