No, the equation is not balanced. It should be written as 2Na + S → 2NaS to show that two sodium atoms combine with one sulfur atom to form two sodium sulfide molecules.
The balanced equation for sodium and chlorine to produce sodium chloride is: 2Na(s) + Cl2(g) -> 2NaCl(s)
The balanced symbol equation for sodium azide is: 2NaN3 (s) → 2Na (s) + 3N2 (g).
2Na(s)+O2(g) ----> Na2O2(s)
The balanced equation for the reaction of sodium with water is: 2Na (s) + 2H2O (l) -> 2NaOH (aq) + H2 (g)
2NH3(g) + 3Mg(s) —> 3H2(g) + Mg3N2(s)
2na+s-2nas
Consider firstly if there are equal numbers of atoms of each element on either side of the reaction. No, there aren't: there are too many sodium, chloride ions and hydrogen atoms on the reactant side, so the equation is not balanced.
The balanced equation for sodium and chlorine to produce sodium chloride is: 2Na(s) + Cl2(g) -> 2NaCl(s)
The balanced symbol equation for sodium azide is: 2NaN3 (s) → 2Na (s) + 3N2 (g).
2Na(s)+O2(g) ----> Na2O2(s)
The balanced equation for the reaction of sodium with water is: 2Na (s) + 2H2O (l) -> 2NaOH (aq) + H2 (g)
koh + h2so4-khso4 +h2o
2NH3(g) + 3Mg(s) —> 3H2(g) + Mg3N2(s)
2Na (s) + 2HCl (aq) -> 2NaCl (aq) + H2 (g)
The balanced equation for sodium reacting with water to yield sodium hydroxide and hydrogen gas is: 2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g)
The balanced complete ionic equation for Na2CO3 (sodium carbonate) and copper nitrate would be: 2Na+(aq) + CO3^2-(aq) + 2Cu2+(aq) + 4NO3-(aq) -> 2Na+(aq) + 2NO3-(aq) + 2CuCO3(s) This equation shows all ions present in the reaction before and after the reaction takes place.
Assuming you're reacting the two, it's 2Na + S --> Na2S.