No that would be a3. 3a is 3 x a. Think of it as 3 a's.
it will be a cube or a to the power of 3.
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
a/(3a) = 1/3
4a7 / 3a3 = ( 4/3 ) x ( a7/a3 ) = 4a4 / 3
-3a-12 = 12+12 +12-3a = +12~ ~-3 -3a = -8
it will be a cube or a to the power of 3.
the 3 in 3a is called a coefficient.
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
a/(3a) = 1/3
The factors of 3a are 3 and a.
-3(a^2 - 3a + 7)
3 a b =3a b
3a2
4a7 / 3a3 = ( 4/3 ) x ( a7/a3 ) = 4a4 / 3
-3a-12 = 12+12 +12-3a = +12~ ~-3 -3a = -8
3a=1divide both sides by 3a=1/3
It is not clear whether the question is 3a + 4a + 5a + 6a^3 which would be 12a + 6a^3 or 3a + 4a + 5a + (6a)^3 = 12a + 216a^3 or (3a + 4a + 5a + 6a)^3 = 5832*a^3 But none of these really require summation notation!