Not exactly because it will have a remainder
490 ÷ 8 = 61 remainder 2
No, it's not.
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490
490 ÷ 58 = 8 times remainder 26, alternatively, using fractions and decimals: 490 ÷ 58 = 8 13/29 ≈ 8.448
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
4 is divisible by 1, 2 and 4. So is 8. If a number is divisible by 8, it will also be divisible by 4.
No, it's not.
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490
no. its divisible by 2 and 10
61.25
1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490.
7 is a factor of 490 but 8 is not.
Any multiple of 490.
If the last 3 digits are divisible by 8, the number is divisible by 8.
490 ÷ 58 = 8 times remainder 26, alternatively, using fractions and decimals: 490 ÷ 58 = 8 13/29 ≈ 8.448
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
Composite; any number ending with zero (besides zero itself) is divisible by 10. 490 = 49 * 10 = 7 * 7 * 5 * 2
Not always for example, 36 is not divisible by 8 but it is divisible by 2 and 4.