As 4 is less than 621, 4 is not divisible by 621. Nor is 621 divisible by 4: 4 is even and all multiples of 4 are even, 621 is odd and so cannot be a multiple of 4. To check divisibility by 4, if the the last 2 digits are divisible by 4, the original number is divisible by 4. For 621, the last 2 digits are 21 and 21 is not divisible by 4, thus 621 is not divisible by 4; nor is 622 since the last 2 digits 22 is not divisible by 4.
47 is a prime number 21 & 87 divisible by 3, and 4 is divisible by 2
85 is not exactly divisible by 4. Dividing 85 by 4 gives 21 with a remainder of 1.
The numeral '21' is evenly divisible by 21, 7, 3, and 1.
They're both divisible by 1,3,7, and 21.
There is nothing that is divisible in 37 and 21. Because 37 is a prime number. However, 21 is divisible by 3 and 7.
4, 8, 12, 16, and 20.
No, it is divisible by: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126
21 is not divisible by 2 nor 5, but it is divisible by 3. To be divisible by 2 the last digit must be even (one of {0, 2, 4, 6, 8}; the last digit 1 is not one of these, thus 21 is not divisible by 2 To be divisible by 3 sum the digits and if this total is divisible by 3, then so is the original number; the test can be repeated on the sum, so by repeatedly summing the digits of the totals until a single digit remains only if that single digit is 3, 6 or 9 is the original number divisible by 3. 21 → 2 + 1 = 3 which is divisible by 3 so 21 is divisible by 3. To be divisible by 5, the last digit must be 0 or 5. The last digit of 21 is 1 which is not 0 nor 5, thus 21 is not divisible by 5.
Because 21 is a multiple of 1, 3, 7 and 21.
The divisibility rule for 3 is as follows: If the sum of the digits of a number is divisible by 3 then the number is divisible by 3. For example, the number 21 is divisible by 3 since 2+1=3, and 3 is divisible by 3. The number 49 is not divisible by 3 since 4+9=13, and 13 is not divisible by 3.
Because 21 is divisible by numbers other than 1 and 21. 21 is divisible by 1, 3, 7, 21