It is an AMPHOTERIC oxide. That is , in an environment of low(acid) pH it behaves as a BASE. In an environment of high(alkaline) pH it behaves as an ACID.
It is an amphoteric oxide.
It is a SALT.
The products are a salt and water.
It is an oxide of alkali metal Cesium, so it is basic in nature,.
Cobalt oxide can refer toCobalt(II) oxide, CoOCobalt(III) oxide, Co2O3Cobalt(II,III) oxide, Co3O4.The three have different properties.
NaOH is a base. HCl is an acid. NaCl is a salt. H2O is an oxide.
It is a SALT.
It is a simple metal oxide, which can make it a salt.
The products are a salt and water.
It is an oxide of alkali metal Cesium, so it is basic in nature,.
Cobalt oxide can refer toCobalt(II) oxide, CoOCobalt(III) oxide, Co2O3Cobalt(II,III) oxide, Co3O4.The three have different properties.
Base forming(metal) oxide eg. CaO, CuO, K2O
NaOH is a base. HCl is an acid. NaCl is a salt. H2O is an oxide.
Neither. Strictly speaking it is a very weak base. A Magnesium Nitrate solution is neutral with a pH of 7.0. Salts of strong acids are neutral. Magnesium Nitrate is salt of Nitric acid which is very strong acid.
Calcium Chloride is neither acid nor base. It is a neutral salt.
Yes, it is acidic:with water it forms an acid (suflurous acid, H2SO3)with base it neutralizes by forming a sulfite salt or (a weaker) base anion SO32-
salt and water. Salt depends on acid
AcidActually, Al2O3 (s) is amphoteric, which means, depending on the environment, it can act as both a base and acid. We are able to illustrate this with these two reactions:(I) - Solving Al2O3 (s) in an acid (HCl):Al2O3 (s) + 6 HCl (aq) → 2 [AlCl3] (s, aq*) + 3 H2O (l)In this reaction, Al2O3 acts as a base-------------------------------------------------------------------(II) - Solving Al2O3 (s) in a base (NaOH):Al2O3 (s) + 3 NaOH (aq) ---> 2 Al(OH)3 (s) + 3 Na+Al(OH)3 (s) then reacts with NaOH to form NaAlO2:Al(OH)3 (s) + NaOH (aq) ---> NaAlO2 (s) + 2 H2O (l)Thus, we often write:Al2O3 (s) + 2 NaOH (aq) → 2 [NaAlO2] (s) + H2O (l)In this reaction, Al2O3 (s) acts as an acid-------------------------------------------------------------------*depending on amount of solvent used. Excessive amounts of solvent will solve the formed AlCl3 (s) into 2([Al3+][Cl-]3) (aq