I'm no chemist, but I do know that you need to balance the sides in this and add another oxygen molecule to the products. the result would be S+H2O2 or SO+H2O (I think).
Wiki User
∙ 11y agoSulphur burns in Oxygen to form Sulphur dioxide in the following reaction: S+O2=SO2 Sulphur dioxide has a capability of reacting with oxygen to form Sulphur trioxide in the following reaction: 2SO2+O2=2SO3 By Prince Sambo Metallurgist
2h2s + so2 ----------> 3s + 2h2o
H2S is only acidic in reference to water(!). Of coarse H2O is neutral referred to water because it is the S A M E .Even water can be both acid A N D base at the same time, though a bit weaker acidic than H2S, but a bit more stronger base.
2hno3+3h2s --> 3s+2no+4h2o
This chemica equation is:B2H6 + 3 O2 = B2O3 + 3 H2O
Sulphur burns in Oxygen to form Sulphur dioxide in the following reaction: S+O2=SO2 Sulphur dioxide has a capability of reacting with oxygen to form Sulphur trioxide in the following reaction: 2SO2+O2=2SO3 By Prince Sambo Metallurgist
2h2s + so2 ----------> 3s + 2h2o
H2S is only acidic in reference to water(!). Of coarse H2O is neutral referred to water because it is the S A M E .Even water can be both acid A N D base at the same time, though a bit weaker acidic than H2S, but a bit more stronger base.
2hno3+3h2s --> 3s+2no+4h2o
Sulphur burns in an oxygen atmosphere to produce sulfur dioxide. When this sag is exposed to hydrogen sulfide it creates pure sulfur. This is the Claus process, the heart of suphur production from sour (hydrogen sulfide rich) gas. In that process the sulphur dioxide comes from the combustion of a portion of the hydrogen sulfide. The reactions are: 2 H2S + 3 O2 → 2 SO2 + 2 H2O (for Hydrogen Sulfide combustion) S + O2 → SO2 (for Sulphur combustion) Whatever the source of the Sulphur Dioxide the reaction with Hydrogen Sulfide is: 2 H2S + SO2 → 3 S + 2 H2O
Here are two chemical reactions:2 SO2 + CH4 = S2 + 2 H2O + CO2SO2 + 2 H2S = 3 S + 2 H2O
This chemica equation is:B2H6 + 3 O2 = B2O3 + 3 H2O
1.40 kg is equal to 1.40 / 0.03418= 40.96 mole H2S, thus 40.96 mole of S (sulfur) which is 40.96 * 0.03207= 1.31 mole S(0.03418 and 0.03207 are molar masses of H2S and S respectively in kg/mol)
4K +O2 --> 2K2O 2Zn + O2 --> 2ZnO 4Fe + 3O2 --> 2Fe2O3 2 Cu+ O2 --> 2CuO K2O +H2O --> 2KOH CaO + 2H2O --> Ca(OH)2 2Na + Cl2 --> 2NaCl 2Fe + 3Cl2 --> 2FeCl3 Zn + S --> ZnS Fe + F --> FeS 3Ca + N2 --> Ca3N2 3Mg + N2 --> Mg3N2 C + O2 --> CO2 S + O2 --> SO2 N2 + O2 --> 2NO 4P + 5O2 --> 2P2O5 SO2 + H2O --> H2SO3 SO3 + H2O --> H2SO4 P2O5 + 3H2O ---> 2H3PO
Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).
The Simple AnswerThe word equation iscarbon dioxide + water => oxygen + glucosewhile the formula equation is6CO2 + 6H2O => 6O2 + C6H12O6To be more precise it is -6CO2 + 12 H2O => C6H12O6 + 6H2O + 6O2 (because O2 comes out from water)
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3