It is polar covalent bond because electrons forming the bond are unequally distributed.
Yes but it is polar
yes it is a polar covalent bond. the difference of electronegativities of H and F is 1.9 , it should be an ionic bond but the ratio of atomic sizes of both the atoms is responsible for polar covalent bond.
No single element can form a bond. Only 2 or more elements can form bonds. Polar bonds occur when there is a dipole moment, or there is asymmetry in the structure. For example, HF forms a polar covalent bond.
Covalent. The bond is polar due to the high electronegativity of fluorine.
HF is a weak polar bond
Yes but it is polar
A good candidate would be the bond in HF.
HF has a polar covalent bond.
yes it is a polar covalent bond. the difference of electronegativities of H and F is 1.9 , it should be an ionic bond but the ratio of atomic sizes of both the atoms is responsible for polar covalent bond.
a very polar, single, covalent bond, yes. This would be an ionic bond. The electronegativity of Hydrogen is about 2.2 and the electronegativity of Fluorine is about 4.0. The difference is 1.8 which is greater than 1.7, the minimum difference for an ionic bond. Or it is (at least) a very polar-covalent bond. Figures 1.7 or 1.8 are in the 'discussion' range
No single element can form a bond. Only 2 or more elements can form bonds. Polar bonds occur when there is a dipole moment, or there is asymmetry in the structure. For example, HF forms a polar covalent bond.
Electronegativity Difference HF = 1.9 = ionic bond HC = 0.4 = nonpolar covalent HH = 0 = nonpolar covalent HN = 0.9 = polar covalent HN is the more polar bond. HF is not polar covalent, it is ionic.
Covalent. The bond is polar due to the high electronegativity of fluorine.
HF is a weak polar bond
Yes! Polar covalent.
Polar (covalent) bonds share electrons in an unequal distrbutium between bith atomic nuclides.
In the increasing order, they are non polar covalent bond < polar covalent bond < ionic bond.