Yes. HNO3 is an electrolyte. In water, it will dissolve into H+ ions and NO3- ions.
no its a strong electrolyte no its a strong electrolyte
wires work pretty good Actually, absolutely dry, anhydrous KNO3 doesn't conduct. In this case, HNO3 is better, In solution, theuy are about the same. The KNO3 solution has nitronium (N3O) ions in it, so does the HNO3. HNO3 in solution, say, 70% , ionizes and cohducts better than 96% red fuming.Either will dissolvey your wires unless platinum.
The chemical formula for nitric acid is HNO3.
I believe it is HNO3
When in doubt, look at the reactants that produce the substance. Potassium nitrate, KNO3, is produced in solution by mixing potassium hydroxide, KOH, and nitric acid, HNO3, which are both strong electrolytes, and so is potassium nitrate. Two strong electrolytes will produce a strong electrolyte, a weak and a strong electrolyte will produce a weak electrolyte, and two weak electrolytes will produce a weak electrolyte.
Nitric acid is an electrolyte.
Yes. HNO3 is a strong acid and therefore a strong electrolyte.
Yes, HNO3 is a strong electrolyte. When it dissociates in water, it forms H+ and NO3- ions, which allows it to conduct electricity.
no its a strong electrolyte no its a strong electrolyte
wires work pretty good Actually, absolutely dry, anhydrous KNO3 doesn't conduct. In this case, HNO3 is better, In solution, theuy are about the same. The KNO3 solution has nitronium (N3O) ions in it, so does the HNO3. HNO3 in solution, say, 70% , ionizes and cohducts better than 96% red fuming.Either will dissolvey your wires unless platinum.
H2SO4Sulfuric acid is a strong acid that disassociates almost 100% in solution.H +andHSO4 -( a further disassociation can take place but that is for college chemistry )And this disassociation is a strong acid disassociation and an electrolyte.
The chemical formula for Hydrogen Nitrate is: HNO3
HNO3 is Nitric Acid
The chemical formula for nitric acid is HNO3.
I believe it is HNO3
HNO3 is called nitric acid.
HNO3 is not neutral.It is a strong acid.