You could argue that it is. Mercury is a metal and iodine is a non-metal, and this typically results in an ionic bond. However, mercury and iodine have a fairly low electronegativity difference (about 0.6) which gives the compound a fair amount of covalent character. In fact, that compound's melting point is about 260 deg. Celsius, which is quite low for an ionic compound (NaCl, by comparison, is 800.) This shows quite a bit of covalent character, since covalent compounds generally have much lower melting points.
Examples: HgO, HgCl2, Hg2Cl2, HgI2, etc.
Mercury (II) Iodine is insoluable in water
Mercury reacts with iodine to form mercuric iodide. Hg(l) + I2(s) = HgI2(s)
COVALENT
covalent
Formula: HgI2
HgI2
HgI2 (with the '2' small subscript - ie below the line)
HgI2
Mercury(II) iodide is HgI2.
Examples: HgO, HgCl2, Hg2Cl2, HgI2, etc.
Mercury(I) iodide = Hg2I2 Mercury(II) iodide = HgI2
yes ALCl3 + 3 C2H5OH =HgI2== AL(OC2H5)3 + 3HCl
Mercury (II) Iodine is insoluable in water
Mercury reacts with iodine to form mercuric iodide. Hg(l) + I2(s) = HgI2(s)
COVALENT
covalent