The hydroxyl radical, as a free radical, is a separate compound and is not part of another compound. However, 'radical' is an archaic term for 'group', and when used in this context, the hydroxyl group can be found in alcohols e.g. ethanol.
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
NaOH and HCl
Alcohols react with NaOH, as ethanol forms sodium ethoxide with NaOH.
NaOH
For example sodium hydroxide ant caesium hydroxide: NaOH, CsOH.
For example sodium hydroxide ant caesium hydroxide: NaOH, CsOH.
The hydroxyl radical, as a free radical, is a separate compound and is not part of another compound. However, 'radical' is an archaic term for 'group', and when used in this context, the hydroxyl group can be found in alcohols e.g. ethanol.
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
208g NaOH
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
NaOH and HCl
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
Alcohols react with NaOH, as ethanol forms sodium ethoxide with NaOH.