Nh3, nh4, n2o4, cn, no2
It is Dinitrogen Tetroxide, also called Nitrogen peroxide. It is a dimer of Nitrogen dioxide, and exists in an equilibrium: NO2 ⇄ N2O4
In the NO2 molecule the nitrogen atom has a single unpaired electron. The molecule will tend to dimerise so that this unpaired electron can be paired with another to form the N2O4 molecule.
well since it getting to old were using a new system because we are flammers
Dinitrogen Teroxide = N2O4 Structure: O2N-NO2
NO2 and N2O4
Nh3, nh4, n2o4, cn, no2
It is Dinitrogen Tetroxide, also called Nitrogen peroxide. It is a dimer of Nitrogen dioxide, and exists in an equilibrium: NO2 ⇄ N2O4
Nitrogenous compounds. NO, NO2, N2O4, NH3, and proteins.
In the NO2 molecule the nitrogen atom has a single unpaired electron. The molecule will tend to dimerise so that this unpaired electron can be paired with another to form the N2O4 molecule.
well since it getting to old were using a new system because we are flammers
Dinitrogen Teroxide = N2O4 Structure: O2N-NO2
Neon, no, it is a noble gas and there are no known compounds. Nitrogen forms a number of oxides, for example, NO, NO2, N2O3, N2O4, N2O5
Assuming you came upon the empirical formula by chemical analysis, the molecular formula would be a multiple of (NO2)n. The vale for n (1, 2, 3 etc) would need to be established by investigation. In this case the molecular formula is N2O4. This molecule is in equilbrium with the monomer NO2. N2O4 is the more common species at low temperatures and is the form found in the solid. NO2 is paramagnetic as it has one unpaired electron.
The empirical mass of NO is 14 + 16 = 30 Divide 138 / 30 ~ = 4.5. The fact that the numbers are not whole number would suggest that the empirical formula is incorrect. However, if we use say NO2 as the empirical formula , then the empirical mass is 14 + 16 + 16 = 46 divide 138 /46 = 3 So NO2 has a formula of N3O6 . This substance does not exist, So it would suggest that the formula is 3NO2 (3/2)N2O4 . I would suggest that the original empirical formula is incorrect. and that the substance is either nitrogen dioxide (NO2) or dinitrogen tetroxide N2O4.
N2O3 is a pale blue solid. Above its melting point of -100 0C it dissociates N2O3 <-> NO + NO2 At low temperatures the liquid is quite an intense blue but fades to a greenish colur due to the presence of NO2. Brown monomeric NO2 is in equilibrium with its dimeric form colourless N2O4
There is no known species as N2O6. NO3 is a transient planar molecule, with an unpaired electron. N2O5 in the solid is NO2+ NO3- in the vapour and solution it is molecular, probably O2-N-O-NO2. N2O4 is a planar molecule O2N-NO2