It is not a synthesis reaction because two products are obtained.
Yes, this is a double displacement reaction where lead nitrate (Pb(NO3)2) and hydrobromic acid (HBr) react to form lead(II) bromide (PbBr2) and nitric acid (HNO3).
The molar mass of PbBr2 is approximately 367.01 g/mol. To find the mass of PbBr2, you would need to know how many moles of PbBr2 you have and then multiply by the molar mass.
The molar mass of PbBr2 is approximately 367.01 g/mol. This is calculated by adding the atomic masses of lead (Pb) and two bromine (Br) atoms.
No, PbBr2 is a weak electrolyte. It only partially dissociates into its ions in water, resulting in a low conductivity compared to strong electrolytes.
When electric current is passed through fused lead bromide, it undergoes electrolysis. The lead bromide breaks down into its constituent elements, lead and bromine, through the oxidation and reduction reactions. The overall equation for this reaction is: PbBr2 (l) -> Pb (l) + Br2 (g)
Pb^2+(aq) + 2Br^-(aq) + Ba^2+(aq) + 2NO3-(aq) → PbBr2(s) + Ba^2+(aq) + 2NO3-(aq) Net ionic equation: Pb^2+(aq) + 2Br^-(aq) → PbBr2(s)
To convert Pb(NO3)2, KBr, PbBr2, and KNO3 into C6H12O6, 6O2, 6CO2, and 6H2O requires a chemical reaction. This specific conversion involves a complex series of steps that would need to be carried out in a laboratory setting under controlled conditions. It is not a direct or simple conversion but rather a multi-step reaction process involving various chemical reactions and potentially multiple intermediate steps.
The molar mass of PbBr2 is approximately 367.01 g/mol. To find the mass of PbBr2, you would need to know how many moles of PbBr2 you have and then multiply by the molar mass.
1.2x10-2
PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
no
The molar mass of PbBr2 is approximately 367.01 g/mol. This is calculated by adding the atomic masses of lead (Pb) and two bromine (Br) atoms.
The chemical formula for lead bromide is PbBr2. It consists of one lead atom bonded to two bromine atoms.
The solubility of PbBr2 at 25°C can be calculated using the Ksp value. Since PbBr2 dissociates into Pb2+ and 2 Br- ions, the solubility (S) can be found using the expression Ksp = [Pb2+][Br-]^2. By substituting the given Ksp value into the equation, you can solve for the solubility of PbBr2 at 25°C.
The formula for Led II Bromide is PbBr2. It is a non organic compound and is a result of leaded gasoline burning.
PbBr2
No, PbBr2 is a weak electrolyte. It only partially dissociates into its ions in water, resulting in a low conductivity compared to strong electrolytes.
Lead(II) Bromide = PbBr2