No Regulus or Alpha Leonis is 23.8 parsecs from the Earth.
Sun apparent mag -26.37. The super need to be closer than 10 parsecs. 6.37/2 Mags. ( light dims by a square law. 5 mags= 100 . 1 Mag 2.5118, 3.19...uh 18.9 closer. 1.7LY?
10 parsecs . . . 32.6 light-years
THat is called the star's absolute magnitude. The standard distance is 10 parsecs.THat is called the star's absolute magnitude. The standard distance is 10 parsecs.THat is called the star's absolute magnitude. The standard distance is 10 parsecs.THat is called the star's absolute magnitude. The standard distance is 10 parsecs.
Hmm... Absolute Mag is measured at 10 parsecs. 5 mags are 100. 20 is 10^8. distance is a square law. So... 10^4 times 10 parsecs, 32,600 Light yesrs. OK?
That means that by definition, the star is at the standard distance of 10 parsecs.That means that by definition, the star is at the standard distance of 10 parsecs.That means that by definition, the star is at the standard distance of 10 parsecs.That means that by definition, the star is at the standard distance of 10 parsecs.
9.99 is closer to 10 than 9.9 is.
Sun apparent mag -26.37. The super need to be closer than 10 parsecs. 6.37/2 Mags. ( light dims by a square law. 5 mags= 100 . 1 Mag 2.5118, 3.19...uh 18.9 closer. 1.7LY?
Basically, that means that the number of tires (2) is closer to 1 than to 10.Basically, that means that the number of tires (2) is closer to 1 than to 10.Basically, that means that the number of tires (2) is closer to 1 than to 10.Basically, that means that the number of tires (2) is closer to 1 than to 10.
|-20 - (-40)| = 20 |-20 - 10| = 30 -20 is closer to -40 than 10.
Your 1 kilometer equals 3.24077649 x 10-14 parsecs. And your second equals 3.16887646 x 10-8 years. Converting kilometers/second to parsecs/year involves multiplying by 3.24077649 x 10-14 and dividing by 3.16887646 x 10-8 to get your answer. Or do that bit of math in advance and then just multiply by 1.022689439 x 10-6 to get your answer. Make sure you have your beginning figure in km per one second. Your answer will appear in parsecs per one year, or just parsecs per year.
10
300mm is 9.72 x 10-18 parsecs.
-5 is larger than -10 because the closer a number is to zero, the larger it is. In this case, -5 is closer to zero than -10.
The square root of 10 is 3.1622776601683793319988935444327, so it is closer to 3 than 4
10
10 parsecs . . . 32.6 light-years
No. Brighter distant stars can have the same apparent magnitude as fainter stars that are closer.(Absolute magnitude does not refer to actual brightness, but rather to what the brightness of a star would likely be at an arbitrary distance of 10 parsecs, rather than its actual distance.)