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It is a compound of tin and fluorine (if it has two parts to its name or ends in -ide, it is not an element).
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∙ 13y ago
Wiki User
∙ 15y agoCompound
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Stannous is Latin for what element?
stannum = tin
What gas helps keep teeth strong when combined with tin?
This compound is tin(II) difluoride - SnF2.
Which pair of elements will most readily form a compound?
elements that may form a compound, are elements that are different from each other, and they also have to be more than 1 element to combine, and create.
Is flouride and fluorine the same thing?
No, fluoride and fluorine are not the same. Fluorine is a chemical element, represented by the symbol F on the periodic table. Fluoride, on the other hand, is an ion or compound that contains fluorine, often formed when fluorine reacts with another element.
Is gravel a compound a element or a element?
It is compound not an element.
Is flouride an element or a compound?
it is an element:D
Is flouride and element or a compound?
compund:D
Is ammonium flouride considered and element or compound?
compound
Is hydrogen cyanide a element compound or mixture?
Hydrogen flouride is a compound.
Stannous is Latin for the element?
tin
Stannous is a latin for the element?
Tin
What element might you find in your toothpaste?
Two common one would be Tin and Fluorine, which make up the anti-cavity compound Stannous Fluoride.
Stannous is Latin for what element?
stannum = tin
What gas helps keep teeth strong when combined with tin?
This compound is tin(II) difluoride - SnF2.
What is the most electromagnetic element after iron?
It is Flouride.
Is it always possible to identify something as an element compound. Substance or mixture just by looking at it?
Very rarely is possible; generally to identify an element or compound it is absolutely necessary to realize a deep chemical/physical analysis.
Is it possible to identify something as an element compound pure substance or mixture just by looking at it?
Very rarely is possible; generally to identify an element or compound it is absolutely necessary to realize a deep chemical/physical analysis.
