answersLogoWhite

0

The element that gives emeralds their beautiful green color is the same element that turns corundum into red rubies. Red Rubies and emeralds are like twins but not the same color.

ITS A CRYSTAL

User Avatar

Wiki User

14y ago

What else can I help you with?

Continue Learning about Chemistry

A reddish brown rock from the Canadian shield was held in a very hot Bunsen burner flame The flame appeared emerald green what metal was most likely present in the rock?

The presence of an emerald green flame indicates that the rock likely contains copper. When copper is heated in a flame, it imparts a distinct green color.


A reddish brown rock from the Canadian shield was held in a very hot Bunsen burner flame The flame appeared emerald green what metal was likely present in the rock?

The presence of an emerald green flame color when heating a reddish brown rock from the Canadian shield suggests the presence of copper in the rock. Copper compounds produce a distinct green flame color when subjected to high temperatures.


How could one describe a metal crystal?

A metal crystal is a solid arrangement of metal atoms in a repeating pattern or lattice structure. These crystals exhibit properties such as high electrical and thermal conductivity, malleability, and ductility. The arrangement of atoms in a metal crystal gives rise to its unique mechanical, electrical, and thermal properties.


What is the coordination geometry of a metal ion in a square planar crystal field?

In a square planar crystal field, the coordination geometry of a metal ion is a flat square shape with four ligands arranged around the metal ion in a plane.


What is the method used to calculate the crystal field splitting energy in transition metal complexes?

The method used to calculate the crystal field splitting energy in transition metal complexes is called the ligand field theory. This theory considers the interactions between the metal ion and the surrounding ligands to determine the energy difference between the d orbitals in the metal ion.