Not a polyhedral shape. You need at least three vertices to define a plane shape. With 5 vertices, the maximum number of triplets you can get is 10 so there cannot be 11 faces.
A sphere has no faces, edges, or vertices.
It is a cuboid that has 8 vertices, 12 edges and 6 faces
There is not a polyhedron with the given number of faces, edges and vertices.
It is a cuboid that has 8 vertices, 12 edges and 6 faces
No, since the numbers of faces, vertices and edges do not satisfy the Euler characteristic.
A sphere has no faces, edges, or vertices.
It has 14 Faces, 24 Edges, and 12 Vertices
It is a cylinder
Sphere ( 0 faces , 0 edges , 0 vertices )
A sphere- there are no faces, edges or vertices
It is a cuboid that has 8 vertices, 12 edges and 6 faces
It is a cuboid that has 8 vertices, 12 edges and 6 faces
There is not a polyhedron with the given number of faces, edges and vertices.
It is a cuboid that has 8 vertices, 12 edges and 6 faces
The shape would be impossible. The faces and vertices have to add up to two more than the edges.
No, since the numbers of faces, vertices and edges do not satisfy the Euler characteristic.
# of faces + # of edges + # of vertecies + 2