It is false. The slope of a straight line on a position-time graph is the average velocity. Slope = y2-y1/x2-x1. On a position-time graph, y is the position (d), and x is the time (t). So y2-y1 = df-di = displacement, and x2-x1 = tf-ti = time interval.
Average velocity = displacement/time interval = df-di/tf-ti
FALSE!
Ahorizontal line on a velocity vs time graph does not indicate any acceleration because there is no slope. Speed remains constant.
The answer is FALSE- acceleration would be correct
ture
Is this a question? or a statement that you are unsure of? Well anyways, this would be correct if acceleration was a constant but if acceleration is not a constant, the (not-constant) acceleration would change the rate of velocity and thus that statement/question would be false.
False
FALSE!
No. Average velocity is still a velocity.Distance is a product of (a velocity or speed) times (a length of time).
It need not be true if 32.2 ft per hour is the average velocity.
it is false .the answer is money stock times velocity of circulations equals average price of transactions times the number of transactions. mv=pt
In physics, total distance/TIME is average speed, so this is false. Velocity should be switched out with TIME.
False.
C. one of the above.
Downward velocity is considered a negative. This is a true statement.
Is the greatest velocity a falling object reaches is called its momentum
that is false as energy is velocity squared, or 4 times
False. The slope of a velocity vs time graph is acceleration