KI or potassium iodide will be basic in solution because it is the product of KOH (a strong base) and HI (a weak acid.)
KI+MnO2+H2SO4=KI+MnSO4+KHSO4+H2O
Sulphuric acid helps in maintaining pH around 3-4 which further helps in liberation of iodine upon adding KI solution.
'KI' is NEITHER an acid NOR a base. It is a (chemical) salt. Ki is potassium iodide.
hno3 + ki ---> kno2 +hi
Hydro iodic acid and potassium hydroxide, HI + KOH ----> KI + H2O
KI+MnO2+H2SO4=KI+MnSO4+KHSO4+H2O
Sulphuric acid helps in maintaining pH around 3-4 which further helps in liberation of iodine upon adding KI solution.
In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
'KI' is NEITHER an acid NOR a base. It is a (chemical) salt. Ki is potassium iodide.
hno3 + ki ---> kno2 +hi
KI
Hydro iodic acid and potassium hydroxide, HI + KOH ----> KI + H2O
Iodine (I), sodium iodide (NaI), potassium iodide (KI), hydroiodic acid (HI)
No, KI is a strong electrolyte. All soluble salts are strong electrolytes, and KI is a salt since it is an ionic compound, but not an acid or a base.
Bhai
I can't find where it is an animal. Ki Ki is a small village South Australia.
The compound is called Potassium Iodide (-ide.. not -ine).