n-3 is three less than n; 3+n is three more than n
They can never be equal
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
6+N3 is the sum of N*3 then you add six. 6*N3 is you multiply 6 times three times N times three.
5+n+3 = 8+n
n3 + 2n2 - 15n = 0 : extract n as a factor of all the left hand terms then, n(n2 + 2n - 15) = 0 : the expression n2 + 2n - 15 can be factored as (n + 5)(n - 3) then, n(n + 5)(n - 3) = 0 : This holds true when either n = 0, or n + 5 = 0 or n - 3 = 0 When n + 5 = 0 then n = -5 : When n - 3 = 0 then n = 3. The solutions are n = 0 or n = -5 or n = 3.
no
Let any number be n:- n3/n3 = n*n*n/n*n*n = 1 And in index form: n3/n3 = n3-3 = n0 = 1
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)
6+N3 is the sum of N*3 then you add six. 6*N3 is you multiply 6 times three times N times three.
The statement n3 is ambiguous. I presume you mean n3, which means n cubed or n to the power of 3 (n*n*n). However, n3 (which should really be written as 3n) means n times 3 (n*3).
5+n+3 = 8+n
n3 + 8n2 + 12n = n(n+2)(n+6)
Let the number be n.Then (n3)3 = n3 x 3 = n9.........or n to the power nine.However, if the question is what the the one-third power of a number cubed, then:(n3)1/3 = n3 x 1/3 = n1 = n
I assume that you mean n = 3 6n + 4 = 6(3) + 4 = 18 + 4 = 22
The chemical formula for a nitride ion is N-3.
N-3.
The N atom is electrically neutral - the number of positively charged protons is equal to the number of negatively charged electrons. That is why there is no net charge on the atom. On the other hand the N3- anion (negatively charged ion) carries a charge of minus 3. It has gain 3 electrons, thereby incurring 3 negative charges. There are 3 more electrons than protons in N3-. N3- can combine with a cation to form an ionic compound.