It can be, but not always so!!!!
For Groupos (I) & (II) the oxidation number is '1' & '2' respectively, the same as the ionic charge.
However, The Oxidation number can vary particularly in the Transition metals. It refers to the number of electrons in the outer (valence) energy shell , that acutally take part in the combination of a chemcial reaction.. NOT all electrons in the outer valence shell take part in a chemcial reaction.
In ionic compounds, the oxidation number is determined by the charge associated with each ion. For cations, the oxidation number is the same as the charge on the ion. For anions, the oxidation number is the negative of the charge on the ion. The sum of the oxidation numbers in an ionic compound must be zero.
Charge refers to the electrical charge of an ion, which is the number of valence electrons gained or lost by an atom. Oxidation number, on the other hand, is a hypothetical charge assigned to an atom in a compound based on a set of rules. The oxidation number can be used to determine the charge of an ion in a compound, but it does not always represent the true charge of the atom.
The oxidation number for CO3 with a charge of -2 is 2.
The oxidation number of a monatomic ion equals its charge. For example, the oxidation number of a sodium ion (Na+) is +1, which matches its charge of +1.
The oxidation number of monoatomic ions is the same as their ion charge: +2 in Fe(II) for Fe2+, +3 in Fe(III) for Fe3+, -2 in sulfide S2-
In ionic compounds, the oxidation number is determined by the charge associated with each ion. For cations, the oxidation number is the same as the charge on the ion. For anions, the oxidation number is the negative of the charge on the ion. The sum of the oxidation numbers in an ionic compound must be zero.
Charge refers to the electrical charge of an ion, which is the number of valence electrons gained or lost by an atom. Oxidation number, on the other hand, is a hypothetical charge assigned to an atom in a compound based on a set of rules. The oxidation number can be used to determine the charge of an ion in a compound, but it does not always represent the true charge of the atom.
It is equal to the charge. Oxidation number depends on charge.
The oxidation number for CO3 with a charge of -2 is 2.
The oxidation number of a monatomic ion equals its charge. For example, the oxidation number of a sodium ion (Na+) is +1, which matches its charge of +1.
The oxidation number of monoatomic ions is the same as their ion charge: +2 in Fe(II) for Fe2+, +3 in Fe(III) for Fe3+, -2 in sulfide S2-
The oxidation number of F, or Fluorine, is F-1. Since it is in the seventh group on the periodic table, it has seven valence electrons. It needs to get eight valence electrons to be stable, so it will gain one electron.
The oxidation number of any monoatomic ion is equal to the charge of the ion. For example, the oxidation number of the sodium ion (Na+) is +1, and the oxidation number of the chloride ion (Cl-) is -1.
The overall oxidation number of an ion is indeed the charge. Na+, sodium is +1 ON, Cl-, chlorine is -1 ON. For a polyatomic ion the charge is the sum of the oxidation numbers of the consituent atoms. For example NH4+ ; N is -3, H is +1 so overall ON is +1 same as the charge.
No. The oxidation number is the charge on the atom of an element, or if the bonding is covalent, what that charge would be if that bonding were ionic. A "molecule" with an electrical charge would be a polyatomic ion, not a molecule.
The most common oxidation number is +II. The charge and number for cobalt is +2.
The oxidation number is the same as the charge that the atom has. If the atom usually loses an electron, then it is losing a negative charge and having more positive making it a + 1. If the atom loses two electrons, then the oxidation number would be +2. The same thing with gaining electrons, then there would be more negative charges then positive. If the atom gains one electron, then the oxidation number would be - 1. If the atom gains two electrons, then the oxidation number would be - 2. I hope that this was helpful.