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What is the simplest radical form of the square root of 160?
4sq 10
What is the square root of 160 rounded to the nearest thousandth?
160.000
How do you simplify the square root of 160?
sqrt(160) = sqrt(16*10) = sqrt(16)*sqrt(10) = 4*sqrt(10)
What is the fifth root of 160?
The fifth root of 160 = 2.759459
What is the simpliest radical form of the square root of 160?
sqrt(160) sqrt(4^2 * 10) = 4sqrt(10) -------------------simplest radical form
What is the square root of 160 simplified?
160/16=10 root 160= root 16 times root 10. root 16= 4 so 4 times root ten is your answer
What is the simplest radical form of the square root of 160?
4sq 10
What 2 numbers can add to get 24 and also multiply to get -160?
The numbers are: 12+square root of 304 and 12-square root of 304
The square root of 160 is between?
√160 = 12.649110641 (or 12.65 to two decimal places). It depends an what is meant by 'between'.
What is the square root of 160 rounded to the nearest thousandth?
160.000
What two consecutive integers does square root of 160 lies?
[object Object]
What is the Square root of 160?
Negative numbers do not have square roots. Multiplying any number by itself will always be a positive number. For example, -1 x -1 is 1. Because two negatives cancel themselves out, and regular numbers are always positive.
How do you simplify the square root of 160?
sqrt(160) = sqrt(16*10) = sqrt(16)*sqrt(10) = 4*sqrt(10)
What is the fifth root of 160?
The fifth root of 160 = 2.759459
What is the radical expression of the square root of 160?
sqrt(160) = sqrt(16*10) = sqrt(16)*sqrt(10) = 4*sqrt(10)
What is the simpliest radical form of the square root of 160?
sqrt(160) sqrt(4^2 * 10) = 4sqrt(10) -------------------simplest radical form
How do you work out 3x squared -10x equals -5?
This is a quadratic expression in x. It cannot be solved because it is an expression: there is no equation to solve. Furthermore, the discriminant for the quadratic = (-10)2 - 4*3*(-5) = 100+60 = 160 which is not a square number. There are, therefore no rational factors. While it would be possible to give irrational factors, factorising a quadratic into linear terms containing irrational numbers is rarely useful.
