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Yes. Free fall can be graphed on a position-time graph and a velocity-time graph.

Refer to the related link below for examples.

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0A falling object doesn't have constant velocity.It has constant acceleration. That means that its velocity increases at a steady (constant) rate.The rate is called the "acceleration of gravity".

-- The rate of acceleration of an object on the moon is(the net force on the object)/(the object's mass) .-- If the object is falling, with nothing but the force of gravity acting on it, thenits acceleration is 1.623 m/s2 (compared to 9.807 on Earth).

An object that has reached its terminal velocity is going at a constant velocity. Acceleration is the rate of change of the velocity. The rate of change is zero. Therefore, the acceleration is zero.

The slope of a straight line tells the rate at which your variables are changing. In this case, it tells you how your velocity is changing over time, which in physics is how we define acceleration. If you graph the velocity of an object vs time when it is falling through the air, it gives to the acceleration due to gravity because that is the acceleration all objects fall at.

Acceleration of a falling object is directly proportional tothe force of gravity in the object's location.

acceleration is the slope of the v t graph... so the acceleration is constant and negative. In other words, the object is slowing down at a constant rate.

A falling object speeds up at a rate of 9.8 meters per second each second.

The rate at which acceleration is changing.

There is not a word for it but it it the rate of change of acceleration.

Rate of change in the acceleration.

The slope at any point is the velocity, so you can construct a graph of that. The slope at any point on that graph is the acceleration. So you can construct a graph of that. The slope at any point on that is the rate of change of acceleration. And so on.

The slope (gradient) of a speed v time graph is acceleration. If the graph is a straight line, then the acceleration is constant. if the slope is 0 (ie the line is horizontal) then the acceleration is 0, and the object is moving with a constant speed (which can be 0, ie the object is stationary). If the graph is "slanted" then depending upon which way the line is "slanted" the object is accelerating or decelerating (the steepness of the slope gives the rate of this). So the object is moving with constant acceleration and either speeding up or slowing down - which, and by how much, depends upon the gradient of the graph.

The acceleration of an object is related to velocity since acceleration is the rate of change of velocity.

the rate of acceleration is very broad as to what you mean, if you mean acceleration as a rate, see my paragraph 2, if you see acceleration change at a rate, see paragraph 3. The rate of acceleration is constant on usually all intervals. Acceleration is defined by the change in speed (velocity) (also note speed is change in distance over time). Acceleration is best described by a car or falling object. If you took a falling object and graphed its distance vs time, you would get a parabola. if you took the derivative of the equation of that graph, you would get the velocity vs time graph. If you then took a third derivative then you would get to the acceleration vs time graph. the acceleration due to earths gravity is 9.8 meters per second squared, or 32 feet per second squared. In that number the average rate of change is that for every second, the velocity increases by 9.8 meters per second. If you mean that acceleration is changing at a rate, then you actual took a third derivative. but for the acceleration to change, you must have an increasing force or decreasing weight (because newtons second law of motion states that Force equals the mass of an object times its acceleration). if you took this approach and graphed it on the distance vs time, you would get a third degree equation (x to the third power), velocity vs time would be parabolic, acceleration vs time would be linear, and the change of acceleration over time to be a constant function.

The rate of acceleration is a measure of the change of the velocity of an object with time. On a graph of velocity versus time, it is represented by the slope of the line so graphed. If velocity is changing in time, the object described is being accelerated. The greater the slope of the graph, the greater the change of velocity per unit of time and the greater the acceleration of that object. true

The rate of change of acceleration (ie. the slope of an acceleration-time graph) is the 'jerk'. It is the third derivative of displacement.

If the speed/time graph slops negatively, that's an indication that the speed is decreasing, i.e. the object is slowing down. The negative slop is also called negative acceleration, since acceleration is the rate of change of velocity.

A distance vs time squared graph shows shows the relationship between distance and time during an acceleration. An example of an acceleration value would be 3.4 m/s^2. The time is always squared in acceleration therefore the graph can show the rate of which an object is moving

This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).

The rate of acceleration.

In the absence of air resistance, a body falling to Earth would accelerate at a rate of approximately 9.8m/s2; gaining 9.8 metres per second velocity every second.

Changing at a constant rate equal to acceleration.

It actually means this. Increase in the rate or speed

No, velocity is the instantaneous speed of an object, the rate of change would be the acceleration of the object.

The rate of acceleration is constant.

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