No. 20 is divisible by these numbers: 1, 2, 4, 5, 10, 20.
Yes.
No.371/3 = 123 2/3 (one hundred and twenty three and two thirds).
It is divisible by three which gives you 247
77922 is divisible by 6. 77922 / 6 = 12987 To check if a number is divisible by 6, the number has to be even and divisible by three. An easy way to check if a number is divisible by three is to see if the sum of the digits is divisible by three. 77922 7+7+9+2+2 =27 27 2+7 =9 9 is divisible by three, so 77922 is divisible by three also.
Five hundred twenty-three
Yes.
None. Twenty-five is not divisible by three.
If the digit in the tens place is divisible by 2 and the digit in the units place is a 0, then the number is divisible by twenty.
No.371/3 = 123 2/3 (one hundred and twenty three and two thirds).
yes
this is a very sad question.
Twenty of them.
Hence the last digits of both 23 and twenty 29 are divisible by three, the whole number is divisible by three, so the highest common factor of both 23 an 29 the answer is 3.
No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
69
No. 3,364 is not divisible by three.
Not evenly.