Love and joy keep all New Zealanders.
lajkanz
lajkanz
Lajkanz
#include <stdio.h> #include <string.h> void stuff(char str[40]); main() { char str[40]; int i; printf("\n enter the string:"); scanf("%s", &str); printf("\n the given string is:"); printf("\n %s", str); stuff(str); } void stuff(char str[40]) { int i, j, k = 0, l, n, z; printf("\n now we are stuffing the data::\n"); n = strlen(str); for (i = 0; i < n; i++) { if (str[i] == '1') { k = 1; for (l = i + 1; l <= i + 5; l++) { if (str[l] == '1') k++; else break; } if (k == 6) { i = i + 6; z = n + 1; for (j = z; j >= i; j--) { str[j] = str[j - 1]; } str[j] = '0'; } } } printf("\nThe resultant string after stuffing is..\n"); printf("%s\n", str); }
l o k n n r z: lo no non nor kor or lorn zonk
L for larynx
a b d e f F g G j J k L m n N p P q Q r R s S t u y z Z
importjava.io.*; classsaddle { publicstaticvoidmain(Stringargs[])throwsIOException { inti,k,j,c1=0,t=0,c2=0,z=0; BufferedReader br=newBufferedReader(newInputStreamReader(System.in)); System.out.println("enter the number of rows in the matrix:"); intn=Integer.parseInt(br.readLine()); System.out.println("enter the number of columns in the matrix:"); intm=Integer.parseInt(br.readLine()); inta[][]=newint[n][m]; System.out.println("enter the elements of the matrix:"); for(i=0;i<n;i++)<span=""> { for(j=0;j<m;j++)<span=""> a[i][j]=Integer.parseInt(br.readLine()); } System.out.println("matrix is:"); for(i=0;i<n;i++)<span=""> { for(j=0;j<m;j++)<span=""> System.out.print(a[i][j]+" "); System.out.println(); } for(i=0;i<n;i++)<span=""> { for(j=0;j<m;j++)<span=""> { z=a[i][j]; c1=0; c2=0; for(k=0;k<m;k++)<span=""> { if(z<=a[i][k]) c1++; } for(k=0;k<n;k++)<span=""> { if(z>=a[k][j]) c2++; } if(c1==m&&c2==n) { t=1; System.out.println("saddle pt="+z); } } } if(t!=1) System.out.println("there is no saddle point"); } }
Going from A to Z, there are 5 letters (H, I, J, K, and L). Going forward to Z and back to A again, there are 19 (N through Z and A through F).
#include <iostream.h> double fact(double n) { return (n > 1) ? n * fact(n - 1) : 1; } double ncr(int n, int r) { return fact(n) / (fact(r) * fact(n - r)); } int main() { for (int i = 0; i < 15; i++) { for (int j = 0; j <= i; j++) cout <<ncr(i, j) << ' '; cout << endl; } return 0; }
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z A B C D E F G H I J K L M N O P Q R S T U V W X Y Z A B C D E F G H I J K L M N O P Q R S T U V W X Y Z A B C D E F G H I J K L M N O P Q R S T U V W X Y Z A B C D E F G H I J K L M N O P Q R S T U V W X Y Z it is alot of work. good luck:)
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern J-Z-L-K-. That is, eight letter words with 1st letter J and 3rd letter Z and 5th letter L and 7th letter K. In alphabetical order, they are: jazzlike