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The specific latent heat of fusion of water is 334 kJ/kg. Ice melts at 0 degrees Celsius and boils at 100 degrees Celsius.
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∙ 9y ago
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∙ 12y ago6.01kJ/mol
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The molar heats of sublimation and fusion of iodine are 62.3kjmol and 15.3kjmol respectively calculate the molar heat of vaporization of liquid iodide?
It is a known fact : Molar heat of sublimation = molar heat of fusion + molar heat of vaporization so, molar heat of vaporization = molar heat of sublimation - molar heat of fusion Mv = 62.3 kJ/mol - 15.3 kJ/mol Mv = 47 kJ/mol.
The molar heat of fusion for water is 6.008 kJmol What quantity of heat energy is released when 253 g of liquid water freezes?
When the molar enthalpy of fusion for water is 6.008 kJ/mol, there is 84.4 kJ released when 253 grams of liquid water freezes. 84.4 kJ
What is the molar heat of fusion of ethanol?
4.931 kj/mol
Molar heat capacity of water?
Molar heat capacity of liquid water = 75.3538 Molar heat capacity = molar mass x specific heat
A sentence for heat of fusion?
Because of the heat of fusion the ice is now water
The amount of heat necessary to change 1 kg of a solid into a liquid at the same temperature is called the?
molar heat of fusion
The molar heats of sublimation and fusion of iodine are 62.3kjmol and 15.3kjmol respectively calculate the molar heat of vaporization of liquid iodide?
It is a known fact : Molar heat of sublimation = molar heat of fusion + molar heat of vaporization so, molar heat of vaporization = molar heat of sublimation - molar heat of fusion Mv = 62.3 kJ/mol - 15.3 kJ/mol Mv = 47 kJ/mol.
The molar heat of fusion for water is 6.008 kJmol What quantity of heat energy is released when 253 g of liquid water freezes?
When the molar enthalpy of fusion for water is 6.008 kJ/mol, there is 84.4 kJ released when 253 grams of liquid water freezes. 84.4 kJ
What is the molar heat of fusion of ethanol?
4.931 kj/mol
What is the relation of the molar heat of fusion to the molar heat of vaporization?
Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
How much heat is requires to convert 0.3 kilogram of ice at 0 C to water at the same temperature?
The molar heat of fusion of water in J / g is 334. To find the heat required to convert 0.3 kg, use the equation: heat of fusion * mass = heat required. It would require 100.2 kJ.
How do you calculate the molar heat of fusion?
Use Einstein's Theory of Special Relativity
Molar heat capacity of water?
Molar heat capacity of liquid water = 75.3538 Molar heat capacity = molar mass x specific heat
How are the heat of fusion of ice and heat of fusion of water similar?
due to the anomalous behaviour of water.....
A sentence for heat of fusion?
Because of the heat of fusion the ice is now water
What is latent heat of fusion of 1kg water?
The latent heat of fusion of 1kg water is 334 kJ/kg. (Wikipedia)
How many calories are released when 35 grams of water at 0 degrees freezes?
You use Heat of fusion... Heat=mass x heat of fusion Heat of fusion for water: 80 cal/g so 35g x 80 cal/g= 2800 cal released.
