Double
2
If spring is cut into two parts, each spring will have it's stiffness doubled. For n parts, stiffness of each part will be nk
Length of compression of the spring = (1.2*9.8)/1800
No, the length doesn't affect the reading because the mass is constant and therefore, the weight is constant. The string's weight is so small that it can be neglected.
Hooke's law is not related to any "natural length". Rather, it defines a string constant: how much the string extends or compresses, depending on the applied force. In SI units, the spring constant would be measured in newton/meter.
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Nothing; it remains the same as before.
If spring is cut into two parts, each spring will have it's stiffness doubled. For n parts, stiffness of each part will be nk
The force constant is unaffected; It is a constant.
Suppose you grab the middle of the spring and hold it perfectly still. Now un-stretch the left half of the spring (the part to the left of where you grabbed it). Nothing about the right half of the spring has changed, so the force applied to the right half of the spring must ( F2 ) be the same F1 we found earlier. visit our page : cndhearingsolution.co.nz/prebooking
Length of compression of the spring = (1.2*9.8)/1800
No, the length doesn't affect the reading because the mass is constant and therefore, the weight is constant. The string's weight is so small that it can be neglected.
Hooke's law is not related to any "natural length". Rather, it defines a string constant: how much the string extends or compresses, depending on the applied force. In SI units, the spring constant would be measured in newton/meter.
no the spring constant is not constant on moon because there is no restoring force there
larger the spring constant of a spring, the more stiffer it is.
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