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On the side on which the force is being applied, the distance and force are directly proportional. On the other side of the lever, they are inversely proportional. If 1 pound of force is applied to a lever at 1 foot on the left side of the fulcrum, the lever will apply 1 pound of force 1 foot from the right side of the fulcrum. If 1 pound of force is applied 2 feet left of the fulcrum, the lever will apply 2 pounds of force 1 foot from the right side. If 1 pound is applied 4 feet left of the fulcrum, the lever will apply 4 pounds of force 1 foot to the right of the fulcrum. If 1 pound of force is applied 1 foot left of the fulcrum, at 2 feet on the right side, the force will be 1/2 pound. At four feet, it will be 1/4 pound. Etc,

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Q: Levers explain how the force applied by a lever is affected by its distance from the fulcrum?
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Related questions

Evaluate would a 9n force applied 2m from the fulcrum lift the wight explain?

A 9-N force cannot be applied 2 m from the fulcrum lift the weight because it wouldn't balance


What are fulcrums?

A fulcrum is the turning point of a lever i.e. The hinge on a door. It is essential to know when learning about the law of the lever i.e. The distance from the fulcrum X force applied on the right hand side = The distance from the fulcrum X force applied on the left hand side. IF the lever is balanced. This can also be written as anticlockwise moments = clockwise moments.


What is the principles of the lever according to Archimedes?

According to Archimedes, the principles of the lever include the Law of the Lever and the Principle of Virtual Work. The Law of the Lever states that the product of the weight being lifted and its distance from the fulcrum is equal to the product of the weight applied to the other end and its distance from the fulcrum. The Principle of Virtual Work states that if a lever is balanced and one side is moved along a circular arc, the distances of the weight and the weight applied to the other end from the fulcrum are inversely proportional to their magnitudes.


If you apply a force of 220 N to the lever how much force is applied to lift the crate?

If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.


What happens if the effort in a class 2 lever is moved closer to the fulcrum?

The torque will be reduced. The torque is found by the cross product of the distance from the fulcrum and the applied force. Assuming the force is applied perpendicular to the lever, you merely multiply the two. So if the force applied remains constant and you shorten the distance to the fulcrum, you are reducing one of the values while the other remains constant. When multiplied, this will reduce the total. Therefore the torque will be reduced. In effect, the lever will have a weaker action.


What is the MA of a first class lever?

It is (distance from fulcrum to effort)/(distance from fulcrum to load).


What is the relationship between distance from the fulcrum and the mechanical advantage of a first class lever?

The mechanical advantage of a First Class lever is Distance of the effort from the fulcrum/Distance of the load from the fulcrum


Does a lever pivot on a fulcrum or a torque?

Fulcrum. Torque is the force applied to move the lever


What is the length from the fulcrum to the load?

That is the distance between the load and the fulcrum. The load may be on the far side, or the near side of the fulcrum. One often overlooked fact, is that as the distance from load to fulcrum increases, the load on the fulcrum decreases.


Describe the distance from the applied force to the fulcrum?

wow i just had a unit in science about this and i cant remember


Point around which a lever rotates?

The fulcrum. A Lever is a rigid rod to which a force can be applied to overcome a resistance. The point at which a lever pivots is called the fulcrum.


When working with lever problems what do the variables Fr Fe Dr and De stand for?

When we work with levers, we look at the lever and at the fulcrum. There are 4 variables in the scenario, and they are the force being applied on one side of the lever, and the force being applied on the other. Then there is the distance from the fulcrum that one force is being applied, and lastly the distance from the fulcrum to where the other force is being applied. The forces are Fr and Fe, and the distances from the fulcrum are Dr and De. (We often actually use F1, F2 and D1, D2.) If everything balances out and a static (stationary) condition exists, F1 x D1 = F2 x D2. (For your variables, Fr x Dr = Fe x De.) The products of the force on one side and distance from the fulcrum on that one side equals that same thing on the other side. Simple and easy.