Hf + oh- ---> f- + h2o
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
The net ionic equation for hydrofluoric acid and potassium hydroxide is HF + OH- -> H2O + F-. This is because hydrofluoric acid (HF) is a weak acid, so it does not completely dissociate in solution. The fluoride ion (F-) acts as a spectator ion in other aqueous reactions because it remains in solution unchanged and does not participate in the reaction.
HCl is a strong acid, while NaOH, HF, and NH3 are not strong acids. NaOH is a strong base, HF is a weak acid, and NH3 is a weak base.
From what I've been told, because HF is a weak acid and therefore a weak electrolyte you are not supposed to break it up into cations and anions. Not sure how you would be getting F- as a spectator in other aq reactions, unless there's an extra rule that I simply haven't been taught.
Sodium fluoride dissolves in water but does not chemically react with water.
The net ionic equation for HF and NaOH is: HF (aq) + NaOH (aq) -> H2O (l) + NaF (aq).
The net ionic equation for the reaction of 1HF and MGCl2, with 2HF and NHbR, would be approximately 2GCF. This can fluctuate a bit, but will wholly depend on if the NHbR changes at all.
Hydrofluoric acid is a weak acid that is slightly soluble in water without much ionic dissociation. The product in the reaction is either pure water or water with a mixture of fluorine atoms.
When aqueous solutions of potassiumfluoride and hydrobromic acid are mixed, an aqueous solution of potassiumbromide and hydrofluoric acidresults. Write the net ionic equation for the reaction.
No it's is HF + (OH)- --> F- + H2O sodium is a spectator ion so it isn't included on each side.
The net ionic equation for hydrofluoric acid and potassium hydroxide is HF + OH- -> H2O + F-. This is because hydrofluoric acid (HF) is a weak acid, so it does not completely dissociate in solution. The fluoride ion (F-) acts as a spectator ion in other aqueous reactions because it remains in solution unchanged and does not participate in the reaction.
HCl is a strong acid, while NaOH, HF, and NH3 are not strong acids. NaOH is a strong base, HF is a weak acid, and NH3 is a weak base.
From what I've been told, because HF is a weak acid and therefore a weak electrolyte you are not supposed to break it up into cations and anions. Not sure how you would be getting F- as a spectator in other aq reactions, unless there's an extra rule that I simply haven't been taught.
Sodium fluoride dissolves in water but does not chemically react with water.
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF → KF + H2O.
The equation for the acid dissociation constant Ka of hydrofluoric acid (HF) is Ka = [H+][F-] / [HF], where [H+] is the concentration of hydronium ions, [F-] is the concentration of fluoride ions, and [HF] is the concentration of hydrofluoric acid.
The acid dissociation constant (Ka) of HF (hydrofluoric acid) is given by the equation: Ka = [H+][F-] / [HF], where [H+] is the concentration of hydrogen ions, [F-] is the concentration of fluoride ions, and [HF] is the concentration of hydrofluoric acid in solution.