Actually, there is such thing as a polyhedron.
Its a 3D shape and it's faces are all the same shapes. Doesn't matter what shape, actually.
^^^
ok, to the dude who answered before me (above):
you're a butt... you didn't answer the freaking question!
Its 6
For all polyhedra: vertices + faces = edges + 2 The given fact is: edges = vertices + 10 → vertices + faces = vertices + 10 + 2 → faces = 12
Such a polyhedron cannot exist. According to the Euler characteristics, V + F - E = 2, where V = vertices, F = faces, E = edges. This would require that the polyhedron had only two faces.
12 vertices A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.
3 faces, 2 edges, and no vertices
4 faces, 6 edges, 4 verticesFour faces, six edges and four vertices.
A polyhedron has 30 edges and 12 vertices. How many faces does it have
A sphere is not a polyhedron because it has no edges, no vertices and no flat faces The word 'polyhedron' means many faces.
It is a triangular prism that has 5 faces, 6 vertices and 9 edges
It has 6 vertices.
For all polyhedra: vertices + faces = edges + 2 The given fact is: edges = vertices + 10 → vertices + faces = vertices + 10 + 2 → faces = 12
eight
6
Such a polyhedron cannot exist. According to the Euler characteristics, V + F - E = 2, where V = vertices, F = faces, E = edges. This would require that the polyhedron had only two faces.
12 vertices A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.
v=60-20
The only thing that can be said that there must be at least 4 faces and at least 6 edges and that the polyhedron must satisfy the Euler criterion which requires that: Faces + Vertices = Edges + 2.
If the object is a convex polyhedron, then, by Euler's characteristics, it should have 23 faces.