The probability of throwing exactly 2 heads in three flips of a coin is 3 in 8, or 0.375.
There are 8 outcomes of flipping a coin 3 times, HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT. Of those outcomes, 3 contain two heads, so the answer is 3 in 8.
The probability of flipping a coin 3 times and getting 3 heads is 1/2
There are 8 permutations of flipping a coin 3 times, or of flipping 3 coins one time. They are, with the permutations of two heads bolded...TTTTTHTHTTHHHTTHTHHHTHHH... thus, the probability of flipping a coin 3 times and getting 2 heads is 3 in 8, or 0.375.
The best way to think about this is the following way: What is the probability of flipping heads once? 1/2 What is the probability of flipping heads twice? 1/4 (1/2 * 1/2) Using this we can derive the equation to find the probability of flipping heads any number of times. 1/2n Using this we plug in 25 for n and get 1/225 or as a decimal 2.98023224 x 10-8 or as odds 1:33,554,432
p(heads)= 0.5 p(heads)^4= 0.0625
You still still have a 1:2 chance of getting heads regardless of the times you flip.
The probability of heads is 0.5 each time.The probability of four times is (0.5 x 0.5 x 0.5 x 0.5) = 0.0625 = 1/16 = 6.25% .
Theoretical is 50% Heads, 50% tails: 30-Heads, 30-Tails (theoretical)
The probability is 25%. The probability of flipping a coin once and getting heads is 50%. In your example, you get heads twice -- over the course of 2 flips. So there are two 50% probabilities that you need to combine to get the probability for getting two heads in two flips. So turn 50% into a decimal --> 0.5 Multiply the two 50% probabilities together --> 0.5 x 0.5 = 0.25. Therefore, 0.25 or 25% is the probability of flipping a coin twice and getting heads both times.
If it is a fir coin, the probability is (1/2)10 = 1/1024.
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
50/50 50/50? This is equal to 1 which would imply the probability of flipping a head is certain. Obviously not correct as the probability of flipping a head in a fair dice is 1/2 or 0.5
The probability of flipping a fair coin four times and getting four heads is 1 in 16, or 0.0625. That is simply the probability of one head (0.5) raised to the power of 4.
1:6 * * * * * No. It is 10/32 = 5/16
1/8. The probability of flipping a coin three times and it landing on head is 1/2, as a coin only has two sides. You flip a coin three times, therefore the answer is (1/2)^3 = 1/8.
It is 3/1024 = 0.00293, approx.
None, since that would imply that in 18 cases the coin did not show heads or tails!
Every time you flip a coin it has a 50% chance of heads and a 50% chance of tails. Flipping a coin multiple times does not change that. Therefore the answer is 50%
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
The probability on the first flip is 50% .The probability on the 2nd flip is 50% .The probability on the 3rd flip is 50% .The probability on the 4th flip is 50% .The probability of 4 heads is (50% x 50% x 50% x 50%) = (0.5)4 = 1/16 = 6.25%
The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.
The probability of getting a heads on the first flip is 1/2. Similarly, the probability on each subsequent flip is 1/2, since they are independent events. The probability of several independent events happening together is the product of their individual probabilities.
Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.
About a 1 in 16 chance of getting a coin to land on heads 4 times in a row.
75% is not correct. The odds of flipping 4 independent coins is the same as flipping one coin 4 times. The number of outcomes of 4 flips is 2^4 or 16. The number of ways to exactly get 3 Heads is 4 (THHH, HTHH, HHTH, HHHT) so your chance of flipping 3 heas is 4/16 or 25%. If you include the occurance that produced 4 of 4 Heads, then you get 5/16 or 31.25%.
Mathematical probability is how many times something is projected to occur, where as experimental probability is how many times it actually occurred. For example, when discussing the probability of a coin landing heads side up... Mathematical probability is 1:2. However, if you actually carryout an experiment flipping the coin 5 times the Experimental probability may be 2:5
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