0
Radiometric titration is "regular" titration, but with the incorporation of a radioactive indicator to monitor the end-point. And that's right from the IUPAC Compendium of Chemical Terminology. If...
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
Example redox titration calculator?
Zn + KNO3 + HCl → ZnCl2 + KCl + NH4Cl + H2O
What is the mole ratio for KCl?
KCl
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
The answer is 6,71 g dried KCl.
How is the bond in F2 different from the bond in KCl?
F2 is covalent and KCl is ionic
Example redox titration calculator?
Zn + KNO3 + HCl → ZnCl2 + KCl + NH4Cl + H2O
What is the mole ratio for KCl?
KCl
What is KCl?
KCL is Potassium Chloride.
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?
0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
What volume of 0.060 M KCl solution contains 2.39g of KCl?
MW KCl = 74.6 g/mol2.39 gKCl * (1 mol KCL/74.6 g KCl)*(1 L solution/0.06 mol KCL) = 0.534 L
What is the compound for KCl?
I'm guessing you meant KCl or potassium chloride.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
What is the solubility of KCl in DMF?
KCl is soluble in DMF
Is KCl an element or compound?
KCl is a compound not an element.
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
