The CuCO3 produces CO2 when it is heated, so the wooden splint will go out since the carbon dioxide would inhibit the oxygen from allowing the splint to stay lit.
The thermal decomposition in this case is: CuCO3 -------------CuO + CO2
It decomposes to form copper oxide and carbon dioxide. It is an endothermic reaction, which means it absorbs heat (as all decomposition reactions do). This is the chemical equation of the reaction: CuCO3 ----> CuO + CO2
The corresponding ionic reaction would be; Cu2+(aq) + CO32-(aq) -> CuCO3(s)
CuSO4 + Na2CO3 --> CuCO3 + Na2SO4
CuSO4 (aq) + Na2CO3 (aq) --> CuCO3 (s) + Na2SO4 (aq)
The thermal decomposition in this case is: CuCO3 -------------CuO + CO2
Copper doesn't react with carbon dioxide at room temperature.
It decomposes to form copper oxide and carbon dioxide. It is an endothermic reaction, which means it absorbs heat (as all decomposition reactions do). This is the chemical equation of the reaction: CuCO3 ----> CuO + CO2
CuCO3 = CuO + CO2
The corresponding ionic reaction would be; Cu2+(aq) + CO32-(aq) -> CuCO3(s)
carbon dioxide [CuCO3 --> CuO + CO2]
on heating copper carbonate decomposes to cupric oxide which is black in colour.
Yes, that is correct. When copper carbonate (CuCO3) is heated, it decomposes into copper(II) oxide (CuO) and carbon dioxide (CO2).
It can be either depending on the reaction. For example. here it is a product. 2Cu + H2O + CO2 + O2 --> Cu(OH)2 + CuCO3 it is a product. While in this reaction CuCO3 + 2HCl --> CuCl2 + CO2 + H2O it is a reactant.
CuSO4 + Na2CO3 --> CuCO3 + Na2SO4
CuSO4 (aq) + Na2CO3 (aq) --> CuCO3 (s) + Na2SO4 (aq)
CuCO3 is bluish-greenish-white. If it is heated to a high enough temperature, it will decompose into Carbon Dioxide and Copper II Oxide, which is black.