the wave's speed v is related to both the frequency f and the wavelength l :v = l f.
Combining the above expression for velocity with the definition of index of refraction, we find a relationship between the wavelength l = v/f in a medium and the wavelength l 0 = c/f in vacuum:
In the above equation, the frequencies cancel because frequency does not change as light moves from one medium to another.
As refractive index of the material of a medium is equal to the ratio of the speed of light wave in vacuum to that in the medium and speed is equal to the product of frequency and wavelength and more over for a given frequency
Refractive index =
wavelength of the light in the medium / wavelength of light in vacuum
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Hello Alcohen2006, no you have given a wrong correction.
C vacuum / C medium = wavelength in vacuum / wavelength in medium
as velocity is directly proportional to the wavelength as frequency remains constant
Mathematically
1/f=(r-1)(R2-R1)/R1R2
This is called the Lens Maker's Formula. The r stands for the relative refractive index of the lens. The R1 and R2 are the radius of curvature of the 2 lenses. The principal f is the focal length of the lens.
depend on the solute,solvent,temperature and wavelength
for a lens, to find the relation between refractive index and focal length, use the lensmaker's formula
n1/f=(n2-n1) (1/r1 + 1/r2)
The relation between the angle of refraction and refactive index is:
Sine i/Sine r=Refractive index
where,i=angle of icidence
r=angle of reflection
They have none. They describe properties that are unrelated.
The focal length of a convex mirror is half of its radius of curvature.
More the curvature of the eye lens, lesser the focal length is. Lesser the curvature, greater the focal length is
because manifying power has inerse relation with that of focal length
Their radii of curvature and the refractive index of the material of the lens.
the curvature mirror the emage of the mirror is virtual
The focal length of a concave mirror is about equal to half of its radius of curvature.
The focal length of a convex mirror is half of its radius of curvature.
The Center of curvature is 2 times the focal length. By the way this is a physics question.
f=|-R/2|
More the curvature of the eye lens, lesser the focal length is. Lesser the curvature, greater the focal length is
physics
because manifying power has inerse relation with that of focal length
Their radii of curvature and the refractive index of the material of the lens.
the curvature mirror the emage of the mirror is virtual
There are three factors affecting the focal length of a lens. 1. refractive index of the material of lens. 2. refractive index of the surrounding medium 3. the radius of curvature of the lens surfaces.
This is a Zoom lens with a focal length of between 75 and 300 mm.
The focal length (a.k.a focus) is exactly half the length of the centre of curvature. ie. F = 1/2 C