25Q + 10D = 160 Q + D = 10 ==> 10Q + 10D = 100 Subtract: 15Q = 60 ==> Q = 4, and then D = 6 Check: 4 times 25 cents = $1.00, 6 times 10 cents = 60 cents, sum = $1.60
The 8 coins are: 3 quarters, 2 dimes, 1 nickel and 2 pennies.
If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.
82 dimes
This question cannot be answered.Assume there is1 nickel. There must be 3 more than that in quarters - that makes4 quarters and there are13 dimes---- that adds up to18
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
8 of them.
8 quarters, 5 dimes
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
The 8 coins are: 3 quarters, 2 dimes, 1 nickel and 2 pennies.
11 dimes.
7 nickels, 4 dimes, and 3 quarters.
If 5 dimes to every 8 quarters that is 5 out of every 13 coins dimes and 8 of 13 coins quarters 5/13 x 520 = 200 dimes
If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.
Mula has 16 dimes and 11 quarters.
25Q + 10D = 160 Q + D = 10 ==> 10Q + 10D = 100 Subtract: 15Q = 60 ==> Q = 4, and then D = 6 Check: 4 times 25 cents = $1.00, 6 times 10 cents = 60 cents, sum = $1.60
There are three possible combinations: 1 quarter and 13 dimes 3 quarters and 8 dimes 5 quarters and 3 dimes
30 quarters equals $7.50 42 dimes equals $4.20 That adds up to 72 coins with a value of $11.70