4.184 joules. The is the specific heat or Cp of water is 4.184 J/mol.
calorie I believe it is one calorie
specific heat capacity
The amount of heat needed is one calorie
calorie
specific
gu icccic
depends on the amount of each but assuming equal amounts of each; 53.5 degrees celsius
Specific temperature is an amount of heat per unit mass required to raise the temperature by one degree Celsius.
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
specific heat
When converting from Celsius to Kelvin you always add 273.15 and subtract the same amount when converting from Kelvin to Celsius thus: -259+273.15=14.15 The answer is 14.15 Kelvin
The amount of heat required to increase the temperature of the substance to 1 degree greater than that of the initial temperature of the body!
false its 1 degrees Celsius
20 degrees Celsius is a temperature or a temperature range on the Celsius scale, where 0 is the freezing point of water and 100 is the boiling point of water. If the air temperature is 20 degrees Celsius, the weather is cool but not cold. If a pot of water is raised in temperature by 20 degrees Celsius it is heated by a set amount. 20 degrees Celsius is the same as 68 degrees Fahrenheit.
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
Fahrenheit would change 10.8 degrees.
depends on the amount of each but assuming equal amounts of each; 53.5 degrees celsius
Specific temperature is an amount of heat per unit mass required to raise the temperature by one degree Celsius.
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
The amount of any given gas that will dissolve in a liquid at a given temperature is directly proportional to the partial pressure of that gas.
specific heat
To lower the temperature of 1 gram of water by 1 degree Celsius would be to remove 1 calorie.