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F = (kq1q2)/(r2)

k = 8.99*109 Nm2/C2

q1 and q2 are both = 1.602*10-19 C

r = 52.9*10-12 m

The magnitude = 8.23*10-8 N

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The magnitude of the force between the electron and proton in a hydrogen atom can be calculated using Coulomb's Law: F = k * |q1 * q2| / r^2, where k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the electron and proton (1.6 x 10^-19 C), and r is the distance between them (52.9 x 10^-12 m). Plugging in these values, the magnitude of the force between the electron and proton is approximately 8.2 x 10^-8 N.

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Q: The electron and proton in a hydrogen atom are 52.9pm apart what is the magnitude of force between them?
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