The lowest whole-number ratio of atoms in a molecule
What you write for an ionic compound is called the formula unit, but the formula unit is almost always the same as the empirical formula. The answer to your question could not be the molecular formula because an ionic compound is not a molecule.
It is an empirical formula.
A formula unit is an empirical formula.
An empirical formula has no data about the structure of a compound.
It has a molecular formula of C10H8 so that would make an empirical formula of C5H4.
What you write for an ionic compound is called the formula unit, but the formula unit is almost always the same as the empirical formula. The answer to your question could not be the molecular formula because an ionic compound is not a molecule.
It is an empirical formula.
No. A molecular formula can be the same as the empirical formula, such as CH4 (methane), because the two component atoms exist in a ratio that cannot be mathematically further broken down - one carbon to four hydrogens. In this case the molecular formula (the actual number of atoms per molecule), and the empirical formula (the simplest ratio of those numbers) is identical. On the other hand, ethane, C2H6 - two carbons to 6 hydrogens - has a molecular formula of C2H6 and a empirical formula of CH3, the ratio of 2 to 6 reduced to its simplest whole number form. Sooooooooooo, the molecular formula will always be equal to or greater than the empirical formula, and the empirical formula will always be equal to or less than the molecular formula. In other words (as if that wasn't enough), the molecular formula will never be less than the empirical formula and the empirical formula will never be greater than the molecular formula, but THE TWO CAN BE EQUAL. Whew!!! Ray
A formula unit is an empirical formula.
CH will be the empirical formula and C12H12 will be the molecular formula
It Has No Empirical Formula.
An empirical formula has no data about the structure of a compound.
It has a molecular formula of C10H8 so that would make an empirical formula of C5H4.
In this instance, the empirical formula is the same as the formula unit: NaNO3
The empirical formula for potassium manganate is KMnO4.
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.
The empirical formula for ribose is C5H10O5.