Force=mass*acceleration -> (70 kg)*(5m/s^2)=350 kg m/s^2 OR 350 N (newtons)
F = ma mass must be in kg
5 = 0.7 a
a = 5/0.7 = 7.143 m/s2
The force F = ma= 700x5= 3500 Newtons.
F = ma= 700 x 5= 3500 Newtons.
3,500 N
3,500 N.
3,500 N.
F = m A = (250) (5) = 1,250 newtons
First the acceleration should be 3ms^-2....not 3 ms2...now the force will be 50*3=150 newton...
I guess you mean a rate of 5 meters per second squared.You can calculate the force using Newton's Second Law. That is, simply multiply the mass times the acceleration.
I'm not entirely sure what the question is asking. I'll take a stab at it though. An object that has a non-zero net force applied to it will move. It will accelerate in the direction of the net force at a rate given by F / m, where F is the net force (N) and m is the mass of the object (kg).
5,400
3,500 N.
B. 5,400 N
F = m A = (250) (5) = 1,250 newtons
First the acceleration should be 3ms^-2....not 3 ms2...now the force will be 50*3=150 newton...
I guess you mean a rate of 5 meters per second squared.You can calculate the force using Newton's Second Law. That is, simply multiply the mass times the acceleration.
No, you do not have to use as much force if you accelerate the ball over a longer distance. This means you are slowing it at a lower rate, but take long enough for the slowing to make a difference.
F=ma: m = 650kg a = 3ms-2 ( m/s2 ) 650 x 3 = 1950N (1.95kN)
5,400 N.
I'm not entirely sure what the question is asking. I'll take a stab at it though. An object that has a non-zero net force applied to it will move. It will accelerate in the direction of the net force at a rate given by F / m, where F is the net force (N) and m is the mass of the object (kg).
5,400 N.
It causes it to accelerate, according to the equation, Force = mass * acceleration. Force should be thought of as the Rate of Change of Momentum of an object. Specifically F=dP/dt. Take the equation F= ma = mdV/dt = d(mV)/dt =dP/dt