The perimeter of a rectangle is 2length +2 width.
the width is x the length is x+4. Plug into the equation
2(x)+2 (x+4)=20
2x+2x+8=20
4x=12
x=3
The width is 3 the length is 7 (3+4)
Area is length times width.
3(7)= 21.
the area is 21 centimeters
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
Length + width = half of perimeter, ie 18 cm. 18 - 4 = 14, 14/2 = 7 so sides are 7 and 11 cm and area = 77sq cm
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
21cm3
It is: 12 units in length
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
the width equals 14 cm. and the length equals 31 cm.
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
shorter side = 10 longer side = 19
Length is 11 and width is 7 and so 11 times 7 = 77 square cm
If the rectangle is 12 feet long and has a perimeter of 40, then the height must be 8. If it is made 6 feet longer, it will have a length of 18 and a height of 8. The new area will be 144.
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.