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2*3.14*[m/(K1+ K2)]1/2

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1w ago

The equivalent force constant for two springs connected in series is calculated as k = 1/(1/k1 + 1/k2). The time period T of the suspended mass can be calculated using T = 2π√(m/k). Plug in the values of k and m to find the time period of the suspended mass.

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Q: The mass 'm' is suspended from two coupled springs connected in series the force constant for springs is k1 and k2 calculate time period of the suspended mass?
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Related questions

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