Suppose the angle is x. Then its complement is 90-x.
So x = (90-x) + 28 = 118 - x
So 2x = 118 and x = 59 (with complement 31).
The first angle is 166 deg and the second is 14 deg.
5 dgs
45 degrees
4.939 radians.
The supplementary angle of 57 degrees is 123 degrees The complementary angle of 75 degrees is 15 degrees So: 123 minus 15 = 108 degrees
The complement is 60 degrees.
An angle and its complement add to 90 degrees. Hence an angle of 41 degrees has 49 degrees as its complement.
In the same way that you subtract and add numbers. Sometimes, though, if the answer is greater than 360 dgrees, you can subtract 360. This is because the angle measure of a whole turn and a bit is the same as the angle measure of the bit.
An angle of 108 degrees does not have a complement because is greater than 90 degrees. Its supplement angle has a measure of 180 - 108 = 72 degrees.
The complement of an angle C is (90 - C) So the complement of an angle of 17.7° is (90 - 17.7) = 72.3°
The complement of an acute angle A is the angle 90° - A. The complement of 13° is 77°.
15°
The complement is how much you have left after you subtract the first angle from 90 degrees.
go off
Suppose the angle is x degrees. Then its complement is 90 - x deg So 90 - x = 4*x ie 90 = 5x or x = 18 degrees.
25
OBTUSE