(1, 5, 6, 6), (2, 4, 6, 6), (2, 5, 5, 6), (3, 3, 6, 6), (3, 4, 5, 6), (3, 5, 5, 5), (4, 4, 4, 6), (4, 4, 5, 5).
Assuming you use two six-sided dice, you can roll a sum of 8 as many times as you want, provided you have enough time to sit there and roll them.
It depends what you mean by outcome. If you are interested in the total number of different outcomes, then there are 6 x 6 x 6 x 6 or 1296 unique possible outcomes. If you are only interested in the total (the sum) of the resulting roll, it can be anything from 4 to 24 so there are just 21 possible outcomes.
Number of possible outcomes of one cube = 6Number of possible outcomes of the other cube = 6Number of possible outcomes of two cubes = 6 x 6 = 36Number of ways to roll a sum of 7 with two cubes = 61 - 62 - 53 - 44 - 35 - 26 - 1Probability of rolling the sum of 7 = 6/36 = 1/6 = (16 and 2/3) percent
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.
If a DIE (not dice) is rolled 90 times, the expected value of the sum of the first and second rolls is 7 if you assume that the die is fair. It does not matter how many times you roll the die, as long as it is at least 2.
Assuming you use two six-sided dice, you can roll a sum of 8 as many times as you want, provided you have enough time to sit there and roll them.
It depends what you mean by outcome. If you are interested in the total number of different outcomes, then there are 6 x 6 x 6 x 6 or 1296 unique possible outcomes. If you are only interested in the total (the sum) of the resulting roll, it can be anything from 4 to 24 so there are just 21 possible outcomes.
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
The probability of a sum of seven if you roll two dice is 6/36 or 1/6. There are 6 ways to roll a 7; (6,1) (5,2) (4,3) (3,4) (2,5) & (1,6) and 36 possible outcomes.
P(A=4) = 1/6 P(A+B=4) = 3/36 = 1/12 I would go with one die.
The probability of getting a sum of 2 at least once is 0.8155
2+6 3+5 4+4
Possible outcomes for one cube = 6 .Possible outcomes for 2 cubes = 6 x 6 = 36 .Ways to roll a sum of 7 = 6 ways,1, 6 . . . 2, 5 . . . 3, 46, 1 . . . 5, 2 . . . 4, 3Probability of rolling a 7 on the first roll = 6/36 = 1/6 .Probability of rolling a 7 on the second roll = 6/36 = 1/6 .Probability of rolling a 7 on the third roll = 6/36 = 1/6 .Probability of rolling a sum of 7 three times in a row = (1/6 x 1/6 x 1/6) = (1/6)3 = 1/216 = 0.00463 = 0.463%Probability of not rolling a sum of 7 three times in a row = 1 - (probability of doing it) = 99.537%
There are 3 ways to roll a sum of four, 5 ways to roll a sum of eight and 1 way to roll a sum of 12. That makes 9 out of 36, or 1/4.
never.. the highest number on a dice is a 6
Without digging too deeply into this question, we can see immediately that it has no solution. -- The largest possible sum of 3 digits is (9 + 9 + 9) = 27 -- 3 times (the largest possible sum of 3 digits) is (3 x 27) = 81 -- 3 times the largest possible sum of 3 digits is smaller than any 3-digit number.