154, 308, 462
154
Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.
2310 has all of those as factors.
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
2 is the smallest prime number. Numbers can't have factors larger than themselves. Zero and one aren't large enough to have prime factors.
The smallest is 192 but there are infinitely many such numbers. For example, take any prime number to the 13th power and the result will have exactly fourteen factors. The smallest is 192.
There isn't one. Negative numbers have prime factors and numbers don't stop. The smallest positive numbers with a prime factor is 2.
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.
Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
2 x 3 x 5 = 30
16 if the prime factors don't have to be distinct. 210 if they do.
36
Prime numbers, raised to a power, have one more factor than their exponents. The smallest prime number is 2. 210 has eleven factors. 210 = 1024
2310 has all of those as factors.
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
2 and 3 are the smallest prime numbers. So answer is 2^3 * 3^3 = 216
Just multiply the first three prime numbers together.